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The 1992 United States presidential election in Montana took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Montana was won by Governor Bill Clinton (D-Arkansas) with 37.63% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 35.12%. Businessman Ross Perot (I-Texas) finished in third with 26.12% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush.[2] It was the first time the state voted for a Democrat since it was won by President Lyndon B. Johnson in 1964.
Results
References
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