United States presidential election in Maine, 1992

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United States presidential election in Maine, 1992

← 1988 November 3, 1992 1996 →
  44 Bill Clinton 3x4.jpg RossPerotColor.jpg 43 George H.W. Bush 3x4.jpg
Nominee Bill Clinton Ross Perot George H. W. Bush
Party Democratic Independent Republican
Home state Arkansas Texas Texas
Running mate Al Gore James Stockdale Dan Quayle
Electoral vote 4 0 0
Popular vote 263,420 206,820 206,504
Percentage 38.77% 30.44% 30.39%

Maine Presidential Election Results by County, 1992.svg
County Results
  Clinton—40-50%
  Clinton—<40%
  Perot—<40%

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

The 1992 United States presidential election in Maine took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Maine was won by Governor Bill Clinton (D-Arkansas) with 38.77% of the popular vote over businessman Ross Perot (I-Texas) with 30.44%. Incumbent President George H. W. Bush (R-Texas) finished in third, close behind Perot, with 30.39% of the popular vote.[1] Despite the Bush family having ties to Maine, Perot beat Bush for second place in the state by a slim margin of 316 votes, making Maine one of two states where Perot finished better than third place, the other being Utah.[2] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.[3]

Results

United States presidential election in Maine, 1992[1]
Party Candidate Votes Percentage Electoral votes
Democratic Bill Clinton 263,420 38.77% 4
Independent Ross Perot 206,820 30.44% 0
Republican George H. W. Bush 206,504 30.39% 0
Libertarian Andre Marrou 1,681 0.25% 0
New Alliance Lenora Fulani 519 0.08% 0
U.S. Taxpayers' Howard Phillips 464 0.07% 0
Write-ins 91 0.01% 0
Totals 679,499 100.0% 4
Voter Turnout (Voting age/Registered) 72%/70%

References

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