United States presidential election in Virginia, 1892
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The 1892 United States presidential election in Virginia took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.
Virginia voted for the Democratic candidate, former President Grover Cleveland over the Republican candidate, incumbent President Benjamin Harrison. Cleveland won the state by a margin of 17.46%.
Results
| United States presidential election in Virginia, 1892[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Grover Cleveland | 164,136 | 56.17% | 12 | |
| Republican | Benjamin Harrison (inc.) | 113,098 | 38.70% | 0 | |
| Populist | James B. Weaver | 12,275 | 4.20% | 0 | |
| Prohibition | John Bidwell | 2,729 | 0.93% | 0 | |
| Totals | 292,238 | 100.0% | 12 | ||
References
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