United States presidential election in Connecticut, 1928

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United States presidential election in Connecticut, 1928

← 1924 November 6, 1928 1932 →
  Herbert Hoover - NARA - 532049.tif AlfredSmith.png
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph Taylor Robinson
Electoral vote 7 0
Popular vote 296,641 252,085
Percentage 53.63% 45.57%

President before election

Calvin Coolidge
Republican

Elected President

Herbert Hoover
Republican

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The 1928 United States Presidential Election in Connecticut took place on November 6, 1928 as part of the 1928 United States Presidential Election which was held throughout all contemporary forty-eight states. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the Republican nominee, Secretary of Commerce Herbert Hoover of California, over the Democratic nominee, Governor Alfred E. Smith of New York. Hoover’s running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith ran with Senator Joseph Taylor Robinson of Arkansas.

Hoover won Connecticut by a narrow margin of 8.06 percent.

Results

United States presidential election in Connecticut, 1928[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Herbert Hoover of California Charles Curtis of Kansas 296,641 53.63% 7 100.00%
Democratic Al Smith of Nebraska Joseph Taylor Robinson of Arkansas 252,085 45.57% 0 0.00%
Socialist Norman Thomas of New York James Hudson Maurer of Pennsylvania 3,029 0.55% 0 0.00%
Communist William Z. Foster of Massachusetts Benjamin Gitlow of New York 738 0.13% 0 0.00%
Socialist Labor Verne L. Reynolds of Michigan Jeremiah D. Crowley of New York 625 0.10% 0 0.00%
N/A Others Others 6 0.01% 0 0.00%
Total 553,124 100.00% 7 100.00%


References

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