United States presidential election in Alabama, 1840
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Lua error in package.lua at line 80: module 'strict' not found. The 1840 United States presidential election in Alabama took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
Alabama voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Alabama by a margin of 8.76%.
Results
| United States presidential election in Alabama, 1840[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 33,996 | 54.38% | 7 | 100.00% | ||
| Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 28,515 | 45.62% | 0 | 0.00% | ||
| Total | 62,511 | 100.00% | 7 | 100.00% | ||||
References
- ↑ Lua error in package.lua at line 80: module 'strict' not found.
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| General articles |
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| Local results |
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| Other 1840 elections |
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