1967–68 Coupe de France
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The Coupe de France's results of the 1967–68 season. AS Saint-Étienne won the final played on May 12, 1968, beating Girondins de Bordeaux.
Round of 16
Team 1 | Score | Team 2 |
AS Saint-Étienne (D1) | 2–1 | Angers SCO (D1) |
FC Metz (D1) | 2–1 | AS Nancy (D2) |
AS Angoulême (D2) | 2–0 | FC Rouen (D1) |
FC Sochaux-Montbéliard (D1) | 2–1 | FC Nantes (D1) |
Girondins de Bordeaux (D1) | 2–0 | Gazélec Ajaccio (CFA) |
RC Strasbourg (D1) | 2–0 | Red Star (D1) |
US Quevilly (CFA) | 1–0 | Olympique Lyonnais (D1) |
USL Dunkerque (D2) | 1–0 | OGC Nice (D1) |
Quarter-finals
Team 1 | Score | Team 2 |
AS Saint-Étienne (D1) | 1–0 | FC Metz (D1) |
AS Angoulême (D2) | 2–1 | FC Sochaux-Montbéliard (D1) |
Girondins de Bordeaux (D1) | 2–1 | RC Strasbourg (D1) |
US Quevilly (CFA) | 4–0 | USL Dunkerque (D2) |
Semi-finals
Replay
Final
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