1920 United States presidential election in Oklahoma

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1920 United States presidential election in Oklahoma

← 1916 November 2, 1920 1924 →
  Warren G Harding portrait as senator June 1920.jpg James M. Cox 1920.jpg EugeneVictorDebs.png
Nominee Warren G. Harding James M. Cox Eugene V. Debs
Party Republican Democratic Socialist
Home state Ohio Ohio Indiana
Running mate Calvin Coolidge Franklin D. Roosevelt Seymour Stedman
Electoral vote 10 0 0
Popular vote 243,831 217,053 25,726
Percentage 50.11% 44.61% 5.29%

President before election

Woodrow Wilson
Democratic

Elected President

Warren G. Harding
Republican

The 1920 United States presidential election in Oklahoma took place on November 2, 1920, as part of the 1920 United States presidential election which was held throughout all contemporary 48 states. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

Oklahoma voted for the Republican nominee, Ohio Senator Warren G. Harding, over the Democratic nominee, Ohio Governor James M. Cox and Socialist nominee Eugene V. Debs of Indiana.

Harding ran with Massachusetts Governor Calvin Coolidge, while Cox ran with Assistant Secretary of the Navy Franklin D. Roosevelt of New York and Debs ran with Seymour Stedman of Illinois.

Harding won the state by a margin of 5.5 percentage points. As a result of his win, Harding became the first Republican presidential candidate to win Oklahoma.

Results

1920 United States presidential election in Oklahoma[1]
Party Candidate Votes Percentage Electoral votes
Republican Warren G. Harding 243,831 50.11% 10
Democratic James M. Cox 217,053 44.61% 0
Socialist Eugene V. Debs 25,726 5.29% 0
Totals 486,610 100.00% 10

References

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