United States presidential election in Rhode Island, 1980

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Main article: United States presidential election, 1980
United States presidential election in Rhode Island, 1980
← 1976 November 4, 1980 1984 →
  Carter cropped.jpg Official Portrait of President Reagan 1981-cropped.jpg JohnAnderson.png
Nominee Jimmy Carter Ronald Reagan John B. Anderson
Party Democratic Republican Independent
Home state Georgia California Illinois
Running mate Walter Mondale George H. W. Bush Patrick Lucey
Electoral vote 4 0 0
Popular vote 198,342 154,793 59,819
Percentage 47.7% 37.2% 14.4%
President before election

Jimmy Carter
Democratic

 Elected President

Ronald Reagan
Republican

Lua error in package.lua at line 80: module 'strict' not found. The 1980 United States presidential election in Rhode Island took place on November 4, 1980 in Rhode Island as part of the 1980 United States presidential election.

The Democratic Party candidate, incumbent President Jimmy Carter, won the state over former California Governor Ronald Reagan by 33,356 votes, giving him one of just seven victories in the election (other than Rhode Island, Carter also carried Maryland, Minnesota, Hawaii, West Virginia, the District of Columbia and his home state of Georgia).

Nationally, Reagan won the election with 489 electoral votes and 50.75% of the popular vote.

Results

United States presidential election in Rhode Island, 1980[1]
Party Candidate Votes Percentage Electoral votes
Democratic Jimmy Carter (incumbent) 198,342 47.7% 4
Republican Ronald Reagan 154,793 37.2% 0
Independent John B. Anderson 59,819 14.4% 0

References

  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
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